Dotter - a card game
Over the years I've attempted game design many times. My approach has always been less than scientific, and sadly unrigorous in the play testing department (my friends' unwillingness to ever try was probably the main culprit, though I was never very insistent).
Nevertheless, I've still come up with a couple that I think have some real potential. This one is very promising and I'd love it if someone out there tried it out. Contact me at yitzhar@veredfamily.net to give me any feedback!
Dotter
Background info
Equipment needed: Standard 54 card deck (with jokers). Cribbage board is helpful but not essential.
Player count: 2-? (Untested with more than 2 so far).
Play time: 20-40 minutes (Estimation, the few games played fell in this range).
Rules
Goal: Get to 121 points 6 times first.
Hand: Varying amount of cards, as will be described below. Cards are placed face down in rows of three in front of each player. Players begin with no cards in hand.
The play: Plays are taken in turns, the first player of the first round being determined arbitrarily. Each turn, players may take one of three actions:
- Draw - The player draws three cards from the deck and places them face down in a row along with their other cards. The cards are not looked at.
- Peek - The player looks at two drawn cards. These may be his or another player's, but both must belong to the same player.
- Score - The player scores three drawn cards. He turns the cards face up and scores as described in the scoring section. The scored cards are then placed in the discard pile. Additional restrictions on scoring in the scoring section.
- 5,7,9. When sorted in ascending order, the difference is 2 between adjacent cards. This series would score 7 + 9 = 16 points.
- 1,3,9. When sorted in ascending order, the quotient is 3 between adjacent cards. This series would score 3 + 9 = 12 points.
- 3,Q,3. The card appearing multiple times is 3. It's multiplicity is 2 (appears twice), so this hand scores 3 * 2 = 6 points.
- J,J,J. The card appearing multiple times is J. It's multiplicity is 3 (appears thrice), so this hand scores 11 * 3 = 33 points.
- A,A,K. In this hand, aces form part of a pair, not a series. So the hand scores 1 * 2 = 2 points.
- 6,10,A. In this hand, the ace is the highest in the series of difference 4. So the hand scores 10 + 14 = 24 points.
- 3,4,A. In this hand, the ace is simply another card of nothing. The highest card is therefore the 4, and the hand scores 4 points.
- Guess: double. Cards: 3,3,8. The guess is correct, so the hand scores 2 * (2 * 3) = 12 points.
- Guess: double. Cards: Q,K,A. The guess is incorrect, so the hand scores by the lowest card. Since the ace isn't forming part of a scoring series, it's the lowest card, and the hand scores 1 point.
- Guess: series, quotient. Cards: J,J,J. The guess is technically correct (the quotient is 1), so the hand scores 2 * (11 + 11) = 44 points. Note: if the player guessed triple, they'd get 2 * (3 * 11) = 66 points instead!
- No player has scored 121 points in the game yet. Player 1 is at 80 points, player 2 at 115. Player 2 scores 20 points. He moves his peg to the 121 spot, and counts his first 121 of the game. Immediately, Player 2 scores 66 points. Instead of going right on to his next 121, Player 2 must wait at the 120 spot until player 1 scores again and starts his next 121.
- Player 1 has completed two laps of 121 points, and is currently on 53 points. Player 2 has completed one lap of 121 points and is on 78 points. So, player 2, leading, retains his points into the next round while player 1 starts from zero.
- Player 1 has completed three laps of 121 point and is currently holding the 121 peg. Player 2 has completed 3 laps and is on 100. Player 3 has completed 4 laps and is on 100. Since the 121 peg counts as part of the next lap, players 2 and 3 retain their points, while player 1 must start from zero. He has still completed his fourth lap of 121 though.
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